sd

Question

sd

psymon · Answer

When you graph simply sin(x) by itself? Maybe you're zoomed out?

anonymous · Answer

i don't know.  I did zoom standard

psymon · Answer

Yeah, I normally would have made the assumption that you're zoomed out too far. Check thevalues of your graph maybe? Like, if you tell it to evaluate sin(x) at pi/2 does it still give you 1 on your graph.

anonymous · Answer

ya

anonymous · Answer

but first can you help me solve the other problems?

psymon · Answer

So those are all separate problems, right?

anonymous · Answer

ya

psymon · Answer

Okay, well witht he first problem we want everything on one side set equal to 0, so we can do that:
$$x ^{3}-3x ^{2}+3x - 1 = 0$$
Have you heard about the rational zeros theorem?

anonymous · Answer

no

psymon · Answer

Well, maybe you heard it and don't know the name, who knows. Well, it says that the "possible" real zeros are factors of the constant divided by factors of the leading coefficient. So our constant is -1 and our leading coefficient is just 1. So these would be the "possible" real zeros:
$$\frac{ \pm -1 }{ \pm 1 }$$ Any combination of those that we can come up with could be a zero. Now these are only possible zeros, only one of them may bean actual zero. So really, the only two choices we have are positive 1 and negative 1. Which one do you want to test?

anonymous · Answer

positive

psymon · Answer

Alright. Do you know about synthetic division?