Question

How do you solve 4x^2y^3/9x^2y

Answer 1

@zepdrix

Answer 2

I need it to be simplified not solved my b

Answer 3

I'd think of it like this:
\[\frac{ (4)(x)(x)(y)(y)(y) }{ 9(x)(x)(y) }\]
So what can happen is if you have an x on top and on bottom it can be cancelled out, since anything divided by itself is 1. Same thing with the y's. If you have one on top and one on bottom, they can cancel out since they become one.
So you have 2 x's on top and 2 x's on bottom. So they can all cancel each other put.
You have 3 y's on top and one y on bottom, so only one of the y's on top and bottom disappear, leaving you with 2 y's left on top