Question

Question Below

Answer 1

Hi! So, can you get any clues from the equation \(f(x)=2^x +2\)?

Answer 2

So it could be either c or d right?

Answer 3

Actually, the \(y\)-intercept is where \(x=0\), and \(f(2)=~2^0+2~=~1+2~=~3\)

Answer 4

For another assignment I had yeah, we get ordered pairs on them right?

Answer 5

:)

Answer 6

Oh that just confused me

Answer 7

Np! Probably just looked at it too fast or something :)

Answer 8

Ha nice pun...

Answer 9

Isn't quadratic something like \(x^2+2x+1\)? I'm not great with math terms, but I thought that's what that was..

Answer 10

as long as it has that x^2
its quadratic

if its

x^3 +3=0
its cubic
in standard form it would look like
x^3 + 0y +3= 0

Answer 11

Where would you get the y^2 from?

Answer 12

its multiplied by 0
you get nothing

Answer 13

Oh, okay, is it okay to discard it since it = 0?

Answer 14

Here's the thing for your problem. Do you know what it means to have a negative exponent?

Answer 15

if you put it in standard form that is
THIS IS NOT YOUR PROBLEM
ITS AN EXAMPLE !!!!!!!


example of a cubic with 2 terms
x^3 + 3 = 0

x^3 +0y^+ 2 +3=0

( hope i did this correctly because i feel pressure on me)

Answer 16

scratch the 2

Answer 17

Haha, no pressure @iforgot !

Answer 18

its a y^2

Answer 19

Thanks for explaining that - I think I remember that :)

Answer 20

so theEric, has shown
\[f(0)=2^0+2=1+2=3\]
so the coordinate of the y-intercept is (0,3)


another point you can find on the line
\[f(x)=2^x+2\]is when x=1, ie (1,?)
\[f(1)=2^1+2=2+2=?\]

Answer 21

Lots and lots of pressure. Negative exponent = the graph goes negative as well? Also, wouldnt you add the 2 and 3 on the equation?

Answer 22

Oh okay

Answer 23

if super smart people are typing for so long i think i am doing something wrong

Answer 24

Lol, hes back! Pressure. But, from what theEric said about negative exponents wouldnt it be d?

Answer 25

So UnkleRhaukus helped you by finding the coordinates at two points, and there is only one graph that actually has those coordinates! Did you see that @Athentsu ?

Answer 26

And it's just like @iforgot 's idea of making a table of values!

So you know, a negative exponent just puts the number into the denominator.
\(5^{(-2)}=\dfrac{1}{5^2}\)

Answer 27

Are you confident in the answer yet?

Answer 28

Yeah, now i am. Im sure its the last one

Answer 29

And I agree! :) Congrats!!

Answer 30

Thanks! You were all a great help.

Answer 31

:)