help me find critical points for this equation:
x^3-x^2+x-3.

Question

help me find critical points for this equation: 
x^3-x^2+x-3.

anonymous · Answer

Find the x-coordinate for which the derivative of this function is equals to 0 or does not exists, then substitute the x values into the equation to get the y-coordinate

theeric · Answer

Do you want to know what a "critical point" is?

theeric · Answer

TURITW 's method will get you to the answer. But feel free to ask questions if necessary - OpenStudy people can help!

anonymous · Answer

right that's what I'm having a problem with... I can't seem to get it to equal zero!

anonymous · Answer

Seems like this function doesn't have any critical points.

anonymous · Answer

really? hmmm

zepdrix · Answer

So what'd you get for your derivative function sorry? :u

anonymous · Answer

3x^2-2x+1?

anonymous · Answer

hello again haha

zepdrix · Answer

Hey :)

Hmm yah that looks right.
If we throw it into the Quadratic Formula:$$\large x=\frac{2\pm\sqrt{2^2-4(3)(1)}}{2(3)}$$
Yah you're right, no real solutions. Looks like we have no critical points :o

zepdrix · Answer

There `is` an inflection point though. Do you have to find that next or no?

anonymous · Answer

hmmm I just have to find the absolute min and max...

anonymous · Answer

i don't know how I would do that without finding the critical point first.

zepdrix · Answer

ya i guess there is no max or min for this function D:

anonymous · Answer

hmmm interesting.. ok!

anonymous · Answer

can you help me with another question? It might be a little more of a hassel...

zepdrix · Answer

sure, open up a new thread c:

anonymous · Answer

k.