Question

Using the given points, determine Δy.

(-3, -5) and (0, 10)


Δy = 3
Δy = 5
Δy = 13
Δy = 15

Answer 1

\[\large \Delta y=y_2-y_1\]

We're given coordinate pairs like this, \(\large (x_1,\;y_1)\qquad(x_2,\;y_2)\)
Do you understand which numbers to use?

Answer 2

wtf is that triangle??????

Answer 3

Lol potato XD It's delta, it means "change". change in y.

Answer 4

what math is this?

Answer 5

WAIT DON"T TELL ME. IS THE CHANGE IN y 15?!?!?!?

Answer 6

no i dont understadn how do??

Answer 7

:DDDDDDDDDDDDDDDDDDDDD im about to take precalc in 9th so :P PARDON MY NAIVE-ness

Answer 8

So y changes from -5 all the way to 10?
Which is a change of 15? :U yay you've got the right idea!

Answer 9

Still confused dan? :( hmm

Answer 10

yeh:?

Answer 11

In this problem our y_2 value is 10.
our y_1 value is -5.

So we subtract those values to get their difference.\[\large \Delta y=10-(-5)\]

Answer 12

dan the ybase2 stands for the second value of y, meaning your SECOND y coordinate.

Answer 13

the two negatives equal a positive. and yea......after that....first grade math ;D

Answer 14

The triangle-thingy threw me off at first tho ...

Answer 15

Gonna take precalc? :o oo fun stuff.. you go over a bunch of cool stuff in there:
Logarithms, Exponentials, Limits, Matrices.

Answer 16

i hate logarithms :P i like matrices :P never heard of limits. and exponentials....since algebra 1

Answer 17

im taking algebra 2 on FLVS. Precalc in 9th isnt the way its supposed to be but who cares XD i wanna take statistics in 12th so.....i gotta do what i gotta do

Answer 18

how do