can we assume no concavities for any function that the power is smaller than x^3? so any function with x^2 would have no concavities?
is x^2 a line or a curve?
curves by default have concavity; lines do not
aren't all x^2 a curve because they are parabolas?
yep
the reason why I asked the first question is because in order to find concavities we need to find the second derivative right?
"need" ?? nah .... but if you want to go that route then fine
haha ok imma keep it simple for myself and still go this route
but when I go this route... for an example like this: (x^2)-3. the second derivative becomes 2.
this is where its throwing me off.
f(x) = x^2 + 6x + 12 f' = 2x + 6 f'' = 2 is a positive value always so this tells us that an +x^2 is always cave up
the points where the concavity changes would possible at f'' = 0 or undefined
hmm ok.. so if my second derivative is just a constant, then its showing me that its always that way no matter what the x is right?
correct; and since the sign demonstrates if its up or down ... +2 is always a cave-up concavity
so the question is asking me to find intervals of the concavity.
they gave me my closed intervals of (0<or equal to x <or equal to 2
so should I just assume that because they gave me those intervals I can say from 2,infinity concave up?
can you show me a pic of it?
they never gave me a picture. or are you asking for the picture of the original graph? I can get that from wolfram...
is the original question asking you for the concavity between 0 and 2 ?
yes.
then its concavity up between 0 and 2; just not too sure how to format that to your solution
if this had to do with a program; then i was asking if you could take a screenshot of the problem to see if i could understand what sort of format they might want is all
yeah... it really doesn't have much info haha but thank you! :)
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