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OpenStudy (dls):
Integrate
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OpenStudy (dls):
\[\Huge \int\limits_{}^{} \sin x . e^x\]
OpenStudy (anonymous):
You want step-wise solution or just answer?
OpenStudy (dls):
I'm caught in an infinite loop using by parts
OpenStudy (dls):
\[\Huge \sin x \int\limits_{}^{} e^x - \int\limits_{}^{} [\cos x \int\limits_{}^{} e^x]\]
OpenStudy (dls):
\[\Huge \sin x. e^x - \int\limits\limits_{}^{} [\cos x . e^x]dx\]
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OpenStudy (anonymous):
\[\large =\sin x e^x-\int e^x\cos x\\ \large \sin x e^x -(e^x\sin x-\int e^x (-\sin x))\]
using by parts again
OpenStudy (dls):
i got the basic idea of what you're gonna do,that changes to I
OpenStudy (anonymous):
now if we let
\[\int e^x \sin x=I\]
\[I=e^x \sin x-e^x\cos x-I\]
\[I=\frac{e^x}{2}(\sin x-\cos x)\]
OpenStudy (dls):
nice :O
OpenStudy (anonymous):
previusly i made a mistake by using sin x instead of cos x
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OpenStudy (dls):
yeah,spotted that one
zepdrix (zepdrix):
Ooo this is a fun integral :D
OpenStudy (dls):
yeah :P
OpenStudy (anonymous):
nice one, ty
OpenStudy (anonymous):
+c
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OpenStudy (dls):
lol yeah
OpenStudy (anonymous):
$$\sin x=\Im\{e^{ix}\}\\\int e^x\sin x\,dx=\Im\int e^xe^{ix}\,dx=\Im\int e^{(1+i)x}\,dx=\dots$$
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