Did I do this right?
[9.05] Part 1: Create your own quadratic equation that cannot be solved by factoring, but can be solved using the quadratic formula. Identify the values of a, b, and c, and find the solutions using the quadratic formula. Show all work to receive credit.
Y = -2x^2 - 7x + 9
a = -2
b = -7
c = 9
x = -(-7)+-√-7^2 – 4(-2)(9)/2(-2)
x = 7+-√121/-4
x = 7 +- 30.25
x = 7 + 30.25 = 37.25
x = 7 – 30.25 = - 23.25
x = 30.25 x = -23.25

Question

Did I do this right?
[9.05] Part 1: Create your own quadratic equation that cannot be solved by factoring, but can be solved using the quadratic formula. Identify the values of a, b, and c, and find the solutions using the quadratic formula. Show all work to receive credit.
Y = -2x^2 - 7x + 9
a = -2
b = -7
c = 9
x = -(-7)+-√-7^2 – 4(-2)(9)/2(-2)
x = 7+-√121/-4
x = 7 +- 30.25 
x = 7 + 30.25 = 37.25
x = 7 – 30.25 = - 23.25
x = 30.25      x = -23.25

anonymous · Answer

Ur x values is wrong

anonymous · Answer

How do I fix it?

anonymous · Answer

It should be (7 +- sqrt 121) / (-4)

anonymous · Answer

Which is (7 +- 11) / (-4)

anonymous · Answer

OH! So I do the top and THEN divide it by -4?

anonymous · Answer

And i think this equation can be solved using factoring

anonymous · Answer

divide everything by 2a

anonymous · Answer

A simple way would be to let b^2 - 4ac becomes a non-perfect square

anonymous · Answer

Example,
I want a = 1
So i am left with b^2 - 4c
Then i choose random numbers for b and c such as b = 4 and c = 2 and see if I got a non-perfect square and indeed i got 8.
So my equation would be
x^2 - 4x + 2 = 0

anonymous · Answer

I rewrote the equation as y = 3x^2 - x + 5...