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e^(x) - e^(-x) - 10 = 0 Having some trouble solving for x on this one.
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can be verified why here: http://en.wikipedia.org/wiki/Hyperbolic_function \[\frac{ e^x - e^{-x} }{ 2 } = \sinh(x)\]
your calculator should have the sinh^{-1} function
make use of inverse hyperbolic function
This question is from a chapter on logarithmic and exponential functions--before the hyperbolic function is introduced. Is that the only way to solve for x?
Alternatively, you can treat this as a quadratic: \[e^x-\frac{1}{e^x}-10=0\\ e^{2x}-1-10e^x=0\] Substitute \(y=e^x\): \[y^2-10y-1=0\]
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Yeah, that is more what I was looking for
lol
So you're multiplying both sides by e^x? Ok--I see it now. Thanks.
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