I have no idea how to do this. does anyone know? (Best answer gets medal)
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Slope intercept form is: y = mx + b m is slope, and b is y-intercept, does that give you an idea on how to start?
sort of but all they give me for the first one is the x intercept and some confusing stuff....lol
It is saying, the line that you are trying to describe, is at a 90 degree angle from the line y = 1/2x -1.
if x is 4 then 1/2x-1 would be 1 right?
The x-intercept is where the line you are trying to describe touches the x-axis, not the line y= 1/2x -1
I'll give you another hint, y = 1/2x -1 looks like it is already in slope-intercept form, so what does this equation tell you about y= 1/2x -1?
Remember, slope intercept form is y = mx + b, and m is the slope of the line, and b is the y-intercept of the line
The two things you should never ask JA are System of equations and this worthless stuff ^ sorry :/
lol its okay. thanks for taking a look at it for me though :) @JA1
No problem :)
@Gio123 did you get your question answered?
so the line has to have all those 3 characteristics?
No they are 3 seperate questions and i already found out the first one so only the 2 and 3 @timo86m @ybarrap
plug in what you know :)
parallel just means same slope obviously so y=mx+b and m = is slope then you must have same slope of m.
so 2 is y=2/3 x + b and plug in the rest 7=2/3 *7+b now solve for b
were did the second 7 come from?
Just to make it look a little more clear: Perpendicular to \(y=\frac{1}{2}x-1\) x-intercept at 4. Parallel to \(y=\frac{2}{3}x+6\) and passes through \((6,7)\) Parallel to \(y=-\frac{1}{4}x-2\) x-intercept at 4.
7=2/3 *+b now solve for b
strange os is not leeting me fix it. suppose to be a 6
since you are given an x,y pair plug those in.6,7
im confused.....
7=(2/3) *7+b y m x b=7/3 if you solve for it then simply put it back into y=mx+b y=(2/3)x+(7/3)
thank you so much @timo86m . Were did you learn to be so good at math?
I know he brought up the \(\|\) slope, but did you get the \(\perp\) slope rules between lines?
@e.mccormick do you know the answer for the third question?
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Parallel lines have the same slope. Perpendicular lines have negative inverse slopes. That tells you the slope of any of these three. Then you use the other information to plug into the formula and solve.
I didn't work it. I know how to answer it. But with what I said, and the one timo86m worked, can you see how to do it?
Well, it is parallel... so what is the slope?
is it -1/4 ?
YES!
So, you have a slope. Now, do you know one point on that line?
Parallel to \(y=-\frac{1}{4}x-2\), x-intercept at 4. \(\leftarrow\) it is hiding in this last bit.
can someone help me please anyone. with the third question..
@robtobey please do #3 please.
whoever does i will be come there fan and give them a metal.
@HonorsStudent please answer the 3rd question for me :)
yeah, please answer it with the steps easily read so i can find out how to do it for the rest of the problems please.
@Gio123 Think about "x intercept at 4" . x intercept is where the line crosses the x axis. The crossing point is (x,0). You have the slope, -1/4 from the given line. Now solve for b now that you know x, y and the slope.
Last question basically gives you b in the equation y=mx + b. Since this is parallel to the first equation, you also know the slope, m. Then you're done!
A plot of the two lines is attached. I leave it to you to identify the equation for each one.
so would this be the equation i have to solve for after everything is pluged in? 0=-1/4(4)+b
I deleted all of my notes related to your problem, however, I believe that is the case.
|dw:1376776895505:dw| is this right? does b=1?
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