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How do I simplify 4c^2(5c^4-3)
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Distribute it out
How do I distribute it?
\[4c^2(5c^4-3)=(4c^3)(5c^4)-(4c^3)(3)\]
*2
\[a^x(a^y)=a^{x+y}\] \[(a^x)^y=a^{x*y}\]
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Alright. So, when I multiply (4c^2) (5c^4) the power because 6? And do I just multiply 4 by 3 or all of it? Sorry, I just got back to school and I'm lost.
becomes*
Yes, you are correct
Is it 20c^6-12c^2?
Yup, that's all you have to do
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Sweet! Thanks
Yup!
Wait. Do you have to subtract the two after that or is it done?
Well the equation you have is like: x^3-x, tell me, can you subtract those?
I don't think so because the power makes it different than the other x so we don't know what it is to subtract, right?
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yup, so you have to leave it as it is.
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