Question

Find the inverse Laplace transform of e^(-5s)/(s^2+3s+2).

Answer 1

this looks like a heaviside function

Answer 2

How do I do it?

Answer 3

separate the laplace and you have e^-(5s)*(1)/(s^2+3s+2)

Answer 4

f(t) will be the inverse laplace transform of (1)/(s^2+3s+2)

Answer 5

do you know the heaviside formula?

Answer 6

No.

Answer 7

ok the eqaution is L{f(t-a)U(t-a)}=e^(-as)F(s)

Answer 8

i mean equation* now you see the equation, we will work backwards to find the LHS of the equation

Answer 9

our U(t-a) will be U(t-5) because and you can see that from the formula e^(-5s) where a=-5

Answer 10

now we have to work on finding f(t) from (1)/(s^2+3s+2)

Answer 11

you have the table in front of you

Answer 12

Okay, I get it.

Answer 13

@Idealist, Heaviside function is the same as unit step function.

Answer 14

How would you do this problem?