Question

Jesse kicks a soccer ball off the ground and in the air with an initial velocity of 29 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?

Answer 1

H(t) = -16t^2 + vt + s
H'(t) = -32t + v
H'(0) = -32(0) + v = 29
v = 29
At maximum height, H'(t) = 0.
-32t + 29 = 0
-32t = -29
t = 29 / 32
H(29 / 32) = -16(29 / 32)^2 + 29(29 / 32) + s = 841 / 64 + s

Answer 2

I don't understand how to solve that equation.

Answer 3

s should be the initial height, which is 0 since the ball is kicked off the ground

Answer 4

So, just divide 841 by 64?

Answer 5

Yes

Answer 6

Alright, thank you.