an airplane is flying on a bearing 23 degrees east of north at 650 mph. express the velocity of the airplane as a vector
90-23 is the angle from the x axis so speed (cos(90-23),sin(90-23))
@amistre64 and then do i find the magnitude of that as my answer?
they give yo the speed (magnitude) already ... 650 a vector is defined as speed and direction the speed is given, the direction is the X,Y parts made form the cos and sin parts
@amistre64 ok but then how is that different from the velocity? I just dont get how to combine them to find the velocity
velocity is a vector .... you are most likely assuming speed and velocity are the same thing ....
speed is how fast velocity is how fast and in which direction
if you are tracking an object; you use velocity: 30 mph to the north, 5 mps to the left
just stating how fast something is moving tells you nothing about where it is headed ....
the speed of the train was: k but where does the train end up? san fransisco or delaware? the velocity of the train was: k(cosa, sina)
ok so for this problem it would be set up like 650 (cos 67, sin 67) but then what do you do to solve it?
that is the solution .... if need be you can approximate the trig values; but thats up to whoever is grading it
oh ok! thank you for your help!!
youre welcome
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