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Mathematics 12 Online
OpenStudy (anonymous):

an airplane is flying on a bearing 23 degrees east of north at 650 mph. express the velocity of the airplane as a vector

OpenStudy (amistre64):

90-23 is the angle from the x axis so speed (cos(90-23),sin(90-23))

OpenStudy (anonymous):

@amistre64 and then do i find the magnitude of that as my answer?

OpenStudy (amistre64):

they give yo the speed (magnitude) already ... 650 a vector is defined as speed and direction the speed is given, the direction is the X,Y parts made form the cos and sin parts

OpenStudy (anonymous):

@amistre64 ok but then how is that different from the velocity? I just dont get how to combine them to find the velocity

OpenStudy (amistre64):

velocity is a vector .... you are most likely assuming speed and velocity are the same thing ....

OpenStudy (amistre64):

speed is how fast velocity is how fast and in which direction

OpenStudy (amistre64):

if you are tracking an object; you use velocity: 30 mph to the north, 5 mps to the left

OpenStudy (amistre64):

just stating how fast something is moving tells you nothing about where it is headed ....

OpenStudy (amistre64):

the speed of the train was: k but where does the train end up? san fransisco or delaware? the velocity of the train was: k(cosa, sina)

OpenStudy (anonymous):

ok so for this problem it would be set up like 650 (cos 67, sin 67) but then what do you do to solve it?

OpenStudy (amistre64):

that is the solution .... if need be you can approximate the trig values; but thats up to whoever is grading it

OpenStudy (anonymous):

oh ok! thank you for your help!!

OpenStudy (amistre64):

youre welcome

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