The equation of a circle is shown below. (x -5)2 + (y + 2)2 = 64 The radius of the circle is ________ units.
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\[(x -5)^2 + (y + 2)^2 = r^2\] \[r^2=64, \qquad r=?\]
if r^2=64 then r equals what?
I actually don't know. :(
So we have r^2=64. To solve for r, take the square root of both sides. r=sqrt(64). Use a calculator if you aren't sure about this one! :)
erm, okay.
What do you mean by both sides?
I got 4096. :(
\[\Large r^2=64\]In the land of math, we can manipulate both sides and the equation stays balanced. So we'll take the square root of r^2 and the square root of 64.\[\Large \sqrt{r^2}=\sqrt{64}\]Squareroot and square are inverse operations of one another, they'll undo each other in this instance.\[\Large r=\sqrt{64}\] Hmm 4096? It sounds like you `squared` your 64. You want to `square root` your 64.
How? Did I happen to Multiply 64 by 64? oops, my mistake. *blushing*
Anyone? :(
Yes you multiplied 64 and 64 :) You want to instead use your calculators \(\large \sqrt{}\quad\)button.
okay. 8
yay good job \c:/
Aww, thanks. Imma medal you! :D
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