Question

How to find inverse of this matrix? \[A =\left[\begin{matrix}e^t&e^{2t}&e^2t\\e^t&e^{2t}&0\\e^t&0&e^{2t}\end{matrix}\right]\]
Please, help

Answer 1

http://www.wikihow.com/Inverse-a-3X3-Matrix

Answer 2

Hope this helps!!

Answer 3

Thanks a lot

Answer 4

UW!!Cheers..:)

Answer 5

one more question, do you know how to take integral of that matrix? integral each entry?

Answer 6

http://www.cs.cornell.edu/cv/ResearchPDF/computing.integrals.involving.Matrix.Exp.pdf
http://en.wikipedia.org/wiki/Matrix_calculus
Thats the best I cud help...SRY!!

Answer 7

Again, thanks for help. This is my stuff. I made many small questions because I want to confirm the small pieces of them before combine them together.

Answer 8

Thats some high level thing u've got goin there.No kiddin!!

Answer 9

Did it really help??Which link helped u more??

Answer 10

sure, it helps a lot.

Answer 11

Which HYPERLINK helped u more??

Answer 12

I'll stick to dat for future problems!!

Answer 13

eugene of matrix A?

Answer 14

\[
\begin{matrix}
&&-(t~e^{t+2}(e^{2t}-x)&+0&+e^{3t}(e^{2t}-x)\\
e^t-x&e^{2t}&e^2t&e^t-x&e^{2t}\\
e^t&e^{2t}-x&0&e^t&e^{2t}-x\\
e^t&0&e^{2t}-x&e^t&0\\
&&(e^t-x)&(e^{2t}-x)^2
\end{matrix}
\]
(e^t-x)(e^2t-x)^2-(t e^(t+2)(e^(2t)-x)+e^(3t)(e^(2t)-x))

http://www.wolframalpha.com/input/?i=%28e%5Et-x%29%28e%5E%282t%29-x%29%5E2-%28t+e%5E%28t%2B2%29%28e%5E%282t%29-x%29%2Be%5E%283t%29%28e%5E%282t%29-x%29%29%3D0

maybe

Answer 15

is the 13 element correct?

Answer 16

\[e^{2}t~or~e^{2t}\]

Answer 17

then all that work was off ...

http://www.wolframalpha.com/input/?i=eigenvales+%7B%7Be%5Et%2Ce%5E%282t%29%2Ce%5E%282t%29%7D%2C%7Be%5Et%2Ce%5E%282t%29%2C0%7D%2C%7Be%5Et%2C0%2Ce%5E%282t%29%7D%7D

Answer 18

I really gotta learn Wolfram!!