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The slope of tangent is the first derivative of the given eqaution. So, the slope is \[3x ^{2}\]. It is given that slope is equal to y coordinate. Then \[3x ^{2}=x ^{3}\]
From the equation we have, \[3x ^{2}-x ^{3}=0\]
Taking x^2 common, we are left with \[x ^{2}\left(3-x \right)=0\]
So from this we get x= 0 and 3
thus, x= 0 and x= 3 are the points which I have to calculate
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