To prove cos 2a = 2 cos^2 a - 1 What do I do from cos^2 a -sin^2 a
use the identity:\[\cos^2(a)+\sin^2(a)=1\]
\( \sin^2 a + \cos^2 a = 1\) \( \cos 2a = 2 \cos^2 a - 1 \) \( \cos 2a = 2 \cos^2 a - (\sin^2 a + \cos^2 a) \) \( \cos 2a = 2 \cos^2 a - \sin^2 a - \cos^2 a \) \( \cos 2a = \cos^2 a - \sin^2 a \)
Ok so then I get to 1 - 2 sin^2 a got it thanks again!
yw :)
you can also get it in terms of cos(a)
Thank you mathstudent too
wlcm
awesome both very helpful :) Trying to learn Precalc in a week >.< found trig was the hardest part lol
I'm sure you'll get the hang of it soon - practice makes perfect! :)
Luckily I have a ton of textbooks to use, just need to see some parts explained and I usually pick it up
thats great - the important point here is that you have the right spirit to learn the subject matter - a rare quality that you should be proud of! :)
Haha thanks :) it's because I got moved up to Calc instead of Precalc this year for some reason and I dont want to get dropped and be bored in class for another year with over 100% xD
:)
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