Question

what is the equation of the line parallel to the line y = 5x + 2 and passes through the point (1, -3)?

Answer 1

what is the slope of \(y=5x+2\) ?

Answer 2

Satellite got this one I will back down.

Answer 3

2

Answer 4

y = mx +b

slope = m

Answer 5

not quite

Answer 6

\[\huge y=\color{blue} mx+\color{red}b\]
\(\color{blue}m\) is the slope and \(\color{red}b\) is the \(y\) intercept

Answer 7

So it's 5

Answer 8

yes it is

Answer 9

and so a parallel line will also have slope \(5\)
your job is to find the line with slope \(5\) through the point \((1,-3)\)
do you know how to do that?

Answer 10

No

Answer 11

lol

Answer 12

ok you want to write the point slope formula
\[y-y_1=m(x-x_1)\] with
\[m=5,x_1=1,y_1=-3\]

Answer 13

do you understand what i am asking you to write?

Answer 14

Yes

Answer 15

Y -3 = 5 ( x - 1)

Answer 16

close, but be careful
\(y_1=-3\) so \(y-y_1=y-(-3)=y+3\)

Answer 17

you should have
\[y+3=5(x-1)\] and now multiply out on the right using the distributive law

Answer 18

Y+3=5x-5

Answer 19

right
then subtract \(3\) from both sides to put it in the form you are asked for

Answer 20

Y=5x-8

Answer 21

Is that correct answer?

Answer 22

@Alisonflowers2015 This is pretty simple the slopes of two parallel line are always equal s=3o according to the st. line equation y=mx+c where m is your slope

the slope of first line y=5x+2 is 5 i.e m1=5

Since second line in parallel to the first line its slope m2=5

Now you cannot use y=mx+c to find the equation of second line because you do not know the y-intercept i.e c. So now you would have to use point slope form of equation to find the equation of the second line since you have the co-ordinates

point slope form of st. line equation (y-y1)=m(x-x1)

taking y1=-3 and x1=1

(y+3)=5(x-1)
y=5x-5-3
y=5x-8

y=5x-8 is the equation of the line which is parallel to line y=5x+2