Question

Solve on the interval (0, 2pi):
1-cos theta =2sqrt3/2

How would I solve this? Thank you :)

Answer 1

first solve for \(\cos(\theta)\)

Answer 2

The 1-cos theta is what's confusing me. I can't see how the answer relates to the unit circle

Answer 3

first of all i am confused by \(\frac{2\sqrt3}{2}\) is that really what it says?

Answer 4

Sure is :/

Answer 5

ok
\[\frac{2\sqrt3}{2}=\sqrt3\] right ?

Answer 6

then you get
\[1-\cos(\theta)=\sqrt3\] so
\[-\cos(\theta)=\sqrt3-1\] and therefore
\[\cos(\theta)=1-\sqrt3\]

Answer 7

after that you are on your own
the only way i could solve this is to say
\[\theta=\cos^{-1}(1-\sqrt3)\] and use a calculator

Answer 8

Oh! Okay, thanks for getting me started. I think I can get it from there.

Answer 9

http://www.wolframalpha.com/input/?i=arccos%281-sqrt%283%29%29

Answer 10

yw

Answer 11

i still think
\[\frac{2\sqrt3}{2}\] is a strange thing to write