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Find the integral ( from 0 to 2): qdq / (8q +5) im trying to use u substitution.
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\[\int_0^2\frac{q}{8q+5}~dq\] Let \(u=8q+5\), so that \(\dfrac{1}{8}du=dq\). Note that \(u=8q+5~\iff~q=\dfrac{u-5}{8}\). Now substitute into the integral, keeping in mind the change in limits: \[\frac{1}{8}\int_5^{21}\frac{\frac{u-5}{8}}{u}~du\\ \frac{1}{64}\int_5^{21}\frac{u-5}{u}~du\\ \frac{1}{64}\int_5^{21}\left(1-\frac{5}{u}\right)~du\\ \]
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