Establish this identity: tan(θ)cot(θ)-sin^2(θ) = cos^2(θ)
hint: cot(x) = 1/tan(x) and sin^2(x) + cos^2(x) = 1
Easy, what's tan and cot in terms of sin/cos?
did you eat magic beans?
Me and Jim have different methods, but same result
Gah. I'll come back to this tomorrow, I've been doing homework for way to long. I'll look at it again tomorrow. Good night. Lol.
it would be easier if you study "The Function Hexagon". It will make trigonometry simple. :) tangent and cotangent are inverse functions right? so therefore it is equal to 1 when multiplied to each other. now you have: 1-sin^2(theta) = cos^2(theta) look back again the formula, sin^2(theta)+cos^2(theta) = 1 if we transpose "sin^2(theta)" to the other side, it will be: cos^2(theta) = 1-sin^2(theta) right? now you proved it. cos^2(theta) = cos^2(theta)
Oh okay I see what you did. and the tan was like adding fractions . . . cot and the tan was like adding fractions . . . Brain fart. Thank you so much for your help. :)
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