What do you mean by the statement like Mn has +7 oxidation state? Something like it has strong +ve electric field and attracts more ..like that? something with respect to that?
@chmvijay
i don't know what do u mean by +ve electric field ,is that effective nuclear charge? or ionic radii ?or polarizing power? +7 mean it can loose Max those electrons in any redox reaction and get stable by noble gas configuration It mean is pore +vely charged bcoz u have removed 7 electron and still the same no of protons are there hence the +ve charge on it is very high :) still u need anything more let me know
The oxide of higher oxidation state of the element is more acidic than that of lower oxidation state.Why? This answer is in reference to that question(from p block)
the electrons config for elemental Mn is [Ar] \(4s^23d^5\) \(Mn^{7+}\) would have lost all those 3d and 4s electrons, either through ionization or through binding with e deficient ligands ("oxidative addition") in terms of it's formal charge.
it mean they are LEWIS ACIDIC RIGHT :) bcoz of electron deficient due to higher oxidation state :)
still confusion in MIND ?
can u please explain my answer... The oxide of element of higher oxn. state will have a stronger +ve electric field and it will interact with water more strongly and hence pull electrons of OH bond more tightly.Therefore release of H+ becomes easy.
okok it will hydrolyze|dw:1376929563771:dw| water to form H+
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