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Chemistry 7 Online
OpenStudy (dls):

What do you mean by the statement like Mn has +7 oxidation state? Something like it has strong +ve electric field and attracts more ..like that? something with respect to that?

OpenStudy (dls):

@chmvijay

OpenStudy (chmvijay):

i don't know what do u mean by +ve electric field ,is that effective nuclear charge? or ionic radii ?or polarizing power? +7 mean it can loose Max those electrons in any redox reaction and get stable by noble gas configuration It mean is pore +vely charged bcoz u have removed 7 electron and still the same no of protons are there hence the +ve charge on it is very high :) still u need anything more let me know

OpenStudy (dls):

The oxide of higher oxidation state of the element is more acidic than that of lower oxidation state.Why? This answer is in reference to that question(from p block)

OpenStudy (aaronq):

the electrons config for elemental Mn is [Ar] \(4s^23d^5\) \(Mn^{7+}\) would have lost all those 3d and 4s electrons, either through ionization or through binding with e deficient ligands ("oxidative addition") in terms of it's formal charge.

OpenStudy (chmvijay):

it mean they are LEWIS ACIDIC RIGHT :) bcoz of electron deficient due to higher oxidation state :)

OpenStudy (chmvijay):

still confusion in MIND ?

OpenStudy (dls):

can u please explain my answer... The oxide of element of higher oxn. state will have a stronger +ve electric field and it will interact with water more strongly and hence pull electrons of OH bond more tightly.Therefore release of H+ becomes easy.

OpenStudy (chmvijay):

okok it will hydrolyze|dw:1376929563771:dw| water to form H+

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