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OpenStudy (anonymous):
sqrt -32
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OpenStudy (jdoe0001):
so, what do you think it's?
OpenStudy (debbieg):
\[\sqrt{-32}=\sqrt{-1}\sqrt{32}=i \sqrt{16x2}=4i \sqrt{2}\]
OpenStudy (anonymous):
I think its 4i sqrt 3
OpenStudy (anonymous):
Sorry sorry it was sqrt of -48
OpenStudy (debbieg):
OK then, since 48=16x3, it is 4i sqrt(3), arrived at as I showed above but with 3 instead of in the product under the radicand. :)
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