The polynomial given below has__ roots(s). 3x^2+4x+3 A. one negative and one positive B. two negative C. two complex D. two positive
Do you know the quadratic formula?
yes
Do you know the discriminant of the quadratic formula? It's the radicand of the quadratic formula.
nope
The discriminant is the part: \(b^2 - 4ac\) Plug in the numbers into the discriminant. Then if the discriminant: 1. = 0, there is one real solution. 2. < 0, there are two complex solutions 3. > 0, there are two different real solutions
i got 20
\(3x^2+4x+3= 0\) compare with \(ax^2 + bx + c = 0 \) a = 3, b = 4, c = 3 \(b^2 - 4ac = 4^2 - 4(3)(3) = 16 - 36 = -20 \) The discriminant is -20, which is negative, or less than zero. What can you conclude about the roots of the polynomial?
B
Read again what I wrote above. I copied it below to make it easier for you to find it. Your discriminant is -20, a negative number. Then if the discriminant: 1. = 0, there is one real solution. \(\color{red}{\bf{2. < 0, there~ are~ two~ complex~ solutions}}\) 3. > 0, there are two different real solutions
thanks bratha
Answer is C. Wlcm.
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