Mathematics
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OpenStudy (anonymous):
x+3y=-28
y=-5x
This is what I've come up with so far
since x=1 i'll use that
1(5x)+3y=-28
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OpenStudy (anonymous):
Timesing 1*5 gives me
5x+3y=-28
OpenStudy (anonymous):
so now whaht?
OpenStudy (ivettef365):
just substitute the y for -5x
you did it to the x
OpenStudy (anonymous):
So I do
5x+3(-5)=-28?
OpenStudy (anonymous):
so 5x-15=-28?
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OpenStudy (anonymous):
This doesn't look right
OpenStudy (e.mccormick):
You still need to solve it for x.
OpenStudy (anonymous):
I don't understand this question at all
OpenStudy (jdoe0001):
hmmm
x+3y=-28
y=-5x
is that the original system of equations?
OpenStudy (e.mccormick):
Also, it looks like you subbed wrong...
\(x+3y=-28 \)
\(y=-5x\)
Means:
\(x+3(-5x)=-28 \)
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OpenStudy (e.mccormick):
Solve that for x. Once you have a number, put that number into either equation in place of x and then you can solve for y.
OpenStudy (anonymous):
OK That makes somewhat more sense
That would give me
x-15x=-28
OpenStudy (anonymous):
Wait is that right?
OpenStudy (e.mccormick):
Yes. But it is not complete. What is x-15x?
OpenStudy (anonymous):
Um...This is easy i should know this
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OpenStudy (anonymous):
x=1 right?
OpenStudy (e.mccormick):
No.
Think aout this for a moment: 1-15=?
OpenStudy (anonymous):
If it is then it's
-14x
OpenStudy (e.mccormick):
x means 1x, which is probably what you meant.
OpenStudy (anonymous):
Right that's what I meant :)
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OpenStudy (e.mccormick):
So we are to:
-14x=-28
Next step?
OpenStudy (anonymous):
x-15x=-28
so -14x=-28
-28/-14
x=2
OpenStudy (anonymous):
Then I plug in 2 into y=-5x
y=-5(2)
y=-10
OpenStudy (e.mccormick):
YES! Now sub in the 2 for x in one of the originals...
Yah, like that. That is it.
OpenStudy (anonymous):
Thanks @e.mccormick :D
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OpenStudy (e.mccormick):
np. have fun!