Question

Simplify completely 18 s t to the fourth power over 52 s cubed t times 16 s cubed over 9 s squared t

A 8 t squared over 13 s

B 8 t over 13 s squared

C 4 t squared over 13 s

D 4 t over 39 s squared

Answer 1

\(\bf \cfrac{18st^4}{52s^3t} \times \cfrac{16s^3}{9s^2}
\implies \cfrac{18stttt}{52ssst} \times \cfrac{16sss}{9sss}\)

see any like-terms to cancel out there?

Answer 2

16SSS 9SSS?

Answer 3

\(\bf s\times s\times s = s^3\\
t \times t\times t\times t = t^4\)

and so on

Answer 4

hmm, I put an extra "s" in the 9, lemme fix that

Answer 5

\(\bf \cfrac{18st^4}{52s^3t} \times \cfrac{16s^3}{9s^2}
\implies \cfrac{18stttt}{52ssst} \times \cfrac{16sss}{9ss}\\
\implies \cfrac{(9)(2)stttt}{(4)(13)ssst} \times \cfrac{(4)(4)sss}{9ss}\)

Answer 6

LOST

Answer 7

well.... ok, what is the answer for say \(\bf \cfrac{2}{2}\)

Answer 8

1

Answer 9

what about \(\bf\cfrac{4}{2}\) ?

Answer 10

YES