Question

1. In 1 kilogram of pure water, the mass of hydrogen atoms is approximately 112 grams, or 0.112 kilograms. What is the energy equivalent of this mass in joules?

Answer 1

You remember the famous equation made by Einstein for mass–energy equivalence?

Answer 2

yes @Frostbite

Answer 3

Perfect! that is the equation we are going to use here.

Answer 4

E=mc^2 @Frostbite

Answer 5

Perfect. Now try set into the equation.
\[c=299.792,458 ~ \frac{ m }{ s }\]

Answer 6

(use the kilo unit) as joule is defined as:
\[\large J=\frac{ kg \times m ^{2} }{ s ^{2} }\]

Answer 7

what is the m/8

Answer 8

m is the mass.

Answer 9

Ok i couldnt tell if that was an 8 or an s I knew what the M stood for

Answer 10

ok now what?

Answer 11

Oh sorry. btw I wrote c wrong (american coma and EU comma :P)
\[\large c=299,792,458 ~ \frac{ m }{ s }\]
So set into the equation:
\[\large E=0.112 \times c ^{2}\] and get E

Answer 12

I didnt get a correct answer @Frostbite

Answer 13

What did you get?

Answer 14

a crazy long number

Answer 15

@Frostbite

Answer 16

\[E=0.122 ~ kg \times (299,792,458)^{2} ~ \frac{ m ^{2} }{ s ^{2} }\]
You can see it is going to be big.

Answer 17

Try write what you get.

Answer 18

1.0964813180589e+16
@Frostbite

Answer 19

I get the same \(1.01 \times10^{16} ~ J \)

Answer 20

so that is the answer? @Frostbite

Answer 21

Use 3 significant digits (best when they only give us 3 significant digits too)

Answer 22

Yep. It should be.

Answer 23

Thanks so much. @Frostbite

Answer 24

No problem at all. Hope it was helpful and similar questions in the future is just right on.