Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?

Question

anonymous · Answer

14.1 feet

 13.7 feet

 13.2 feet

 15.2 feet

anonymous · Answer

$$v=30,s=0$$ so the equation is 
$$h(t)=-16t^2+30t$$

anonymous · Answer

max is at the vertex
first coordinate of the vertex is $-\frac{b}{2a}$ which in your case is $$-\frac{30}{2\times -16}=\frac{30}{32}=\frac{15}{16}$$

anonymous · Answer

or if you perfere $.9375$ 
for the second coordinate of the vertex, which is what you are looking for, compute 
$$-16(.9375)^2+30\times .9375$$ with a calculator

anonymous · Answer

so what is it

anonymous · Answer

it is this http://www.wolframalpha.com/input/?i=-16%28.9375%29^2%2B30%28.9375%29

anonymous · Answer

14.1??:)

anonymous · Answer

yeah that is the closest