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Precalculus
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\[\frac{ (x ^{-4}y ^{3})^{-4} }{ (y ^{2}x ^{-6)^{-5}} }\]
when dividing variable expressions like this, you just subtract the exponents
so dividing x^(-4) by x^(-6) gives you x^(-4 - (-6)) = x^(-4 + 6) = x^2
oh wait you first need to multiply the outer exponent of -5 by each of the inner exponents in the denominator
then you can use that subtraction rule
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hmm let me redo
so i'd be like -4--4 so the exponent would be x^0? and then 3--4 would be y^7?
\[\large \frac{ (x ^{-4}y ^{3})^{-4} }{ (y ^{2}x ^{-6)^{-5}} }\] \[\large \frac{ x ^{-4*(-4)}y ^{3*(-4)} }{ y ^{2*(-5)}x ^{-6*(-5)} }\] \[\large \frac{ x ^{16}y ^{-12} }{ y ^{-10}x ^{30} }\] now you can use that subtraction rule
So i'd be |dw:1376948242545:dw| ?
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