Question

You've got to convert the grams to mg (for some of them). Then use the molar mass to convert grams to moles. Finally, make sure you have the serving size in Liters. Then do moles / liters to get molarity. This is their info......

Answer 1

Hey @amyamanda
I don't think you are going to get anyone here to do your homework. I mean the text under your username explain pretty well what you have to do.
But we are ready to help you, if you got a more specific question to your homework.

Answer 2

@Frostbite
I don't know how to convert grams to moles with molar mass, if u could just show me how with one, and then I will follow ur example

Answer 3

Right:
The relation between mass and moles are given with the equation:
\[\Large n=\frac{ m }{ M }\]
n is the amount of substance [mol]
m is the mass [gram]
M is the molar mass [gram/mol]

The molar mass for a molecule is given by:
\[\Large M=\sum_{i}^{}v _{i}m _{i}\]
Where v is the amount for the specific atom and m is the mass for the specific atom.

Lets try use this for sugar.
We assume that when they write "sugar" they mean "sucrose" (VERY IMPORTANT TO WRITE)
Sucrose have the molecular formula \(C_{12}H_{22}O_{11}\)
So the molar mass is:
\[\large M(C_{12}H_{22}O_{11})=12\times m(c)+22 \times m(H)+ 11 \times m(O)\]
Use the periodic table to find the masses. The final unit become gram/mol.

Answer 4

I get \(M(C_{12}H_{22}O_{11})\) to 342.30 g/mol.
So we are now able to find the amount of sucrose in Gatorade:
\[\large n(C_{12}H_{22}O_{11})=\frac{ m(C_{12}H_{22}O_{11}) }{ M(C_{12}H_{22}O_{11}) }=\frac{ 43 ~ g }{ 342.30 ~ \frac{ g }{ mol } }=0.126 ~ mol\]
Now we need the volume, which I can see you haven't given me, in order to calculate the concentration.

Answer 5

what?

Answer 6

volume?

Answer 7

so confused!!!!!??

Answer 8

Is something I have written confusing?

Answer 9

yes

Answer 10

What part?

Answer 11

everything after The molar mass for a molecule is given by:

Answer 12

Okay what I said is that if we have a molecule for example water, then the molar mass is the same as taking each atom mass and add them together. for water \(H_{2}O\):
\[\large M(H _{2}O)=m(H)+m(H)+m(O)=2 \times m(H)+m(O)\]

Answer 13

ok

Answer 14

A bit more understandable? :)

Answer 15

yes

Answer 16

Perfect. So I need the volume in order to calculate the concentration. How many litters or milliliters were there 34 gram sugar? (Darn I wrote 43) CORRECTION:
\[\large n(C_{12}H_{22}O_{11})=\frac{ m(C_{12}H_{22}O_{11}) }{ M(C_{12}H_{22}O_{11}) }=\frac{ 34 ~ g }{ 342.30 ~ \frac{ g }{ mol } }=0.0993 ~ mol\]

Answer 17

how do i find that out it was in a drink?

Answer 18

How much Gatorade where there?

Answer 19

1

Answer 20

1 what? 1 litter?

Answer 21

1 bottle

Answer 22

And how much does one bottle contain? I don't drink Gatorade, so I got no clue :P

Answer 23

335ml

Answer 24

Nice. \(335 ~ ml=0.335 ~ l\).
So now we can calculate the concentration \(C\):
\[\Large C=\frac{ n }{ V }\]

For the sugar in the Gatorade:
\[\large C(C _{12}H _{22}O _{11})=\frac{ n(C _{12}H _{22}O _{11}) }{ V }=\frac{ 0.0993 ~ mol }{ 0.335~l }=0.296 ~ M\]
And there for have it. The concentration of sucrose/sugar in Gatorade.

Answer 25

And there we have it*