Question

Check my question
Given f (x) = x^2 + 7 and g (x) = x-4/x Find (g o f) (-1)
http://gyazo.com/ac76df5601d02ebc0b4a44a… picture of the prob

Answer 1

Given f (x) = x^2 + 7 and g (x) = x-4/x Find (g o f) (-1)

g∘f(x) = f(x) – 4/f(x) = (x^2 + 7) – 4/(x^2 + 7)

So, g∘f(-1) = ((-1)^2 + 7) – 4/((-1)^2 + 7) = 8 – 4/8 = 7.

Answer 2

How do I write the answer as a fraction

Answer 3

\frac{num here}{den here} start it off with \( \\\( \text{ and close it with } \\\) \)

Answer 4

So 4/8

Answer 5

you can test it around at http://mathb.in/

Answer 6

The thing is it can be only a fraction like #/# Only one number on both sides

Answer 7

\(\bf \color{blue}{f (x)} = x^2 + 7\\
g(x) = x-\cfrac{4}{x}\\
(g o f) (-1) \implies g(f(-1))\\
g(f(-1)) = (\color{blue}{f(-1)}) -\cfrac{4}{(\color{blue}{f(-1)})}\)