Question

PLEASE HELP!
HOW DO YOU SOLVE THIS!!!

Answer 1

umm answer choices?

Answer 2

\[\sqrt[3]{125}=5\]

Answer 3

Oh, I know the answer but I want to know the steps to solve it please,

Answer 4

hmm i forgot how to do with the variaables

Answer 5

did u try like subtraction way or division way?

Answer 6

Umm i've tried about everything but I just can't seem to get it

Answer 7

like\[\sqrt[3]{x ^{7}} = 7\div3= x ^{2}\sqrt[3]{x}\]

Answer 8

liek this

Answer 9

than ull get the answer^^

Answer 10

\[\sqrt[3]{x ^{4}}=x \sqrt[3]{x}\]

Answer 11

so basically multiplay them and ull get answer

Answer 12

Sorry I don't get it

Answer 13

watch

Answer 14

wait u dont get the division part?

Answer 15

like the method as a whole, sorry

Answer 16

u know tihs one right?\[\sqrt[3]{125}=5\]

Answer 17

i get that

Answer 18

ok when there is varialbe liek this\[ \sqrt[3]{x ^{4}}\]

Answer 19

already understand it?

Answer 20

yea i don't get how to solve from that point

Answer 21

than u divide like 4/3 which is 1 remainder 1 right

Answer 22

already understand it?

Answer 23

wait why are you dividing it though and yup thanks alexis048

Answer 24

its a rule i shoudl say?

Answer 25

okay

Answer 26

ur teacher didnt teach u this?

Answer 27

umm no

Answer 28

ok so now solve the problem since u know than ull get the answer

Answer 29

wait i'm still confused what you do after you divide 4/3

Answer 30

ok see\[\sqrt[3]{x ^{4}}=x \sqrt[3]{?}\]

Answer 31

since remainder 1 u put ?=x

Answer 32

so x goes under the radicand?

Answer 33

radical****

Answer 34

yes

Answer 35

but what about the x^7

Answer 36

\[x \sqrt[3]{x}\]

Answer 37

its 7divide by 3 so its 2 remainder 1

Answer 38

which is \[x ^{2}\sqrt[3]{x}\]

Answer 39

get it?

Answer 40

kind of

Answer 41

try it by urself if ur getting the answer

Answer 42

Combine like terms and expand it out:
\(2\sqrt[3]{5*5*5*x^3*x^3*x^3*x^2}\)

Answer 43

look he divided cuz radicals are the inverse of \[x^{n}\]

Answer 44

umm okay haha i'm trying it on paper

Answer 45

so if you have \[x^{3}\]=x*x*x

Answer 46

then \[x^{1/3}=\sqrt[3]{x}\]

Answer 47

Any terms that have 3 copies can be removed from the \(\sqrt[3]{~~~}\)
\(2*5*x^3\sqrt[3]{x^2}\)
\(10x^3\sqrt[3]{x^2}\)

Answer 48

and that is equal to 1/x*x*x

Answer 49

Just remember; \[\sqrt[n]{x^n}=x\] and \[x^ax^b=x^{a+b}\]

so:
\[\sqrt[3]{x^3}=x\] and \[\sqrt[3]{x^6}=\sqrt[3]{x^3x^3}=x^2\] and so on....
and \[\sqrt[3]{x^7}=\sqrt[3]{x^3x^3x}=x^2\sqrt[3]{x}\]

Answer 50

i think i got it lol

Answer 51

kk

Answer 52

ok good luck then

Answer 53

thanks everyone! :D

Answer 54

if you want a little more info here is a short video
http://www.khanacademy.org/math/algebra/exponent-equations/exponent-properties-algebra/v/simplifying-cube-roots

the other videos might help, too