Simplifying a log expression: http://oi41.tinypic.com/n4i4o7.jpg

I changed it to (logx^2/logx^5) - (logx^2) but I don't know where to go from there or if that's even the right start.

Question

Simplifying a log expression: http://oi41.tinypic.com/n4i4o7.jpg

I changed it to (logx^2/logx^5) - (logx^2) but I don't know where to go from there or if that's even the right start.

anonymous · Answer

use the fact that log(x^n)=n*log(x)

anonymous · Answer

$$\frac{ 2\log(x)-5\log(x) }{ 5\log(x)-3\log(x) }=\frac{ -3\log(x) }{ 2\log(x) }=\frac{ -3 }{ 2 }$$

anonymous · Answer

I am sorry it's plus in the nuemerator!

anonymous · Answer

Gotcha. And thank you, that is soo helpful! :)

anonymous · Answer

becomes 7/2

anonymous · Answer

you are soo welcome :)