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Mathematics 16 Online
OpenStudy (anonymous):

Simplifying a log expression: http://oi41.tinypic.com/n4i4o7.jpg I changed it to (logx^2/logx^5) - (logx^2) but I don't know where to go from there or if that's even the right start.

OpenStudy (anonymous):

use the fact that log(x^n)=n*log(x)

OpenStudy (anonymous):

\[\frac{ 2\log(x)-5\log(x) }{ 5\log(x)-3\log(x) }=\frac{ -3\log(x) }{ 2\log(x) }=\frac{ -3 }{ 2 }\]

OpenStudy (anonymous):

I am sorry it's plus in the nuemerator!

OpenStudy (anonymous):

Gotcha. And thank you, that is soo helpful! :)

OpenStudy (anonymous):

becomes 7/2

OpenStudy (anonymous):

you are soo welcome :)

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