Graph the function.
so... amplitude is -3/4. horizontal shift in right direction by pi/4.
these options are pretty damn nice. Horizontal shift in the right direction by pi /4. Recall that original sine function has (0,0). this point has been moved to (pi/4,0). What is the only option with such point (pi/4, 0)
B?
does B have (pi/4, 0)?
I think so
@ option B, when x= pi/4, you have y value of -1
Hmmm, I don't think I am understanding this correctly.
draw a regular sine graph. now reduce the amplitude from 1 to 3/4, then flip the entire graph about the x axis, then move the entire graph to the right by pi/4 units.
What is amplitude?
It is the vertical displacement from the x axis to the positive max, or equivalentyl, vertical displacement from the x axis to the negative max. In regular sine graph, notice the function oscillates around -1 and 1. the distance between x axis and positive max of 1 is 1. thus amplitude is 1.
when amplitude is 3/4, its positive max would be 3/4, and negative max would be -3/4. Thus the function will oscillates between (-3/4 and 3/4)
Looking like D
its actually c. Consider (0,0) from the original sine graph.
in this nice case, there is no vertical shift. This indicates that (0 0) from the original sine graph becomes (pi/4,0). In other words, when x= pi/4, y=0. This condition is met only at option c.
Ok, thanks.
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