Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (explainitlikeimfive):

Graph the function.

OpenStudy (explainitlikeimfive):

OpenStudy (anonymous):

so... amplitude is -3/4. horizontal shift in right direction by pi/4.

OpenStudy (anonymous):

these options are pretty damn nice. Horizontal shift in the right direction by pi /4. Recall that original sine function has (0,0). this point has been moved to (pi/4,0). What is the only option with such point (pi/4, 0)

OpenStudy (explainitlikeimfive):

B?

OpenStudy (anonymous):

does B have (pi/4, 0)?

OpenStudy (explainitlikeimfive):

I think so

OpenStudy (anonymous):

@ option B, when x= pi/4, you have y value of -1

OpenStudy (explainitlikeimfive):

Hmmm, I don't think I am understanding this correctly.

OpenStudy (anonymous):

draw a regular sine graph. now reduce the amplitude from 1 to 3/4, then flip the entire graph about the x axis, then move the entire graph to the right by pi/4 units.

OpenStudy (explainitlikeimfive):

What is amplitude?

OpenStudy (anonymous):

It is the vertical displacement from the x axis to the positive max, or equivalentyl, vertical displacement from the x axis to the negative max. In regular sine graph, notice the function oscillates around -1 and 1. the distance between x axis and positive max of 1 is 1. thus amplitude is 1.

OpenStudy (anonymous):

when amplitude is 3/4, its positive max would be 3/4, and negative max would be -3/4. Thus the function will oscillates between (-3/4 and 3/4)

OpenStudy (explainitlikeimfive):

Looking like D

OpenStudy (anonymous):

its actually c. Consider (0,0) from the original sine graph.

OpenStudy (anonymous):

in this nice case, there is no vertical shift. This indicates that (0 0) from the original sine graph becomes (pi/4,0). In other words, when x= pi/4, y=0. This condition is met only at option c.

OpenStudy (explainitlikeimfive):

Ok, thanks.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!