Someone please help ! Earl's savings account has an APR of 7.3%, calculates interest daily, and pays interest at the end of the month. If during the month of June, his balance was $400 for the first 10 days of the month, $1500 for the next 10 days of the month, and $600 for the last 10 days of the month, how much total interest did Earl earn in June?
I need help please
what part you need help with?
I don't understand how to solve it
400(.073/365)^10 1500(.073/365)^10 600(.073/365)^10 seems about right to me
when I try to solve it none of it is adding up to the answer choices A. $3.00 B. $2.80 C. $5.00 D. $2.30
hmm, lets see if ive read it correctly
APR of 7.3%, calculates interest daily i spose we could use 1+.073/365 to get a total balance at the end of 30 days 400 for 10 days: 400(1+.073/365)^10 1500 for 10 days: 1500(1+.073/365)^10 600 for 10 days: 600(1+.073/365)^10 2500 for 10 days should be the same thing ... 2500(1+.073/265)^10 = 2506.90 minus the 2500 would be about 7 bucks .. yeah, i see the issue
lol, 365 .. i typoed it
2500(1+.073/365)^10 = 2505 so about 5 bucks
lol yeah this problem confused me because I m usually good at math
even if we compounded at 360 we would still amount to about 5 bucks extra
the key is: each balance is compounded for 10 days, so just think of them as separate accounts and add up the results
im still confused is there a formula for this?
there is the compound interest formula:\[A=P(1+\frac rn)^{nt}\]
thankyou
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