Question

To find the sum of consecutive integers, starting at 1, we use the formula n(n+1)/2 where n is the last number. Find the sum of the numbers from 1 to 100.

1 + 2 + 3 + ... + 100
A.101
B.1,001
C.5,000
D.5,050

Answer 1

where you see an \(n\) in \(\frac{n(n+1)}{2}\) put a \(100\) and compute

Answer 2

i say its B.

Answer 3

that would be wrong

Answer 4

how tho?

Answer 5

So its A.

Answer 6

idk im lost lol

Answer 7

what you need to do is to take the \(n\) in the expression
\[\large \frac{n(n+1)}{2}\] and replace it by \(100\) then see what you get

Answer 8

im so lost on that one too