A heavy crate applied a force of 2,000 N on a 50-m2 piston. What force needs to be exerted on a 1.00 m2 piston to lift the crate?
i beleive: force times surface area should equal or is it force/sa ?
at any rate, there is a ration of Fa/Fb equal to the ratio of the surface areas
So How would I go about solving it? And strangely (or sadly) enough I wasn't given a formula!
its similar in thinking to a seesaw; the fat kids have to sit closer to balance out the skinny kid at the end
f1/f2 = sa1/sa2
you know f1 sa1 and sa2
I think I do but I forgot what fl sal and sa2 stand for
f for force, sa for surface area ...
OK So to solve for the question A heavy crate applied a force of 2,000 N on a 50-m2 piston. What force needs to be exerted on a 1.00 m2 piston to lift the crate?
So do I divide 1.00 m2 by 50-m2?
errr times
\[\frac{F_1}{SA_1}=\frac{F_2}{SA_2}\] \[F_1\frac{SA_2}{SA_1}=F_2\]
2000*1/50
OH OK!
One second
A heavy crate applied a force of 2,000 N on a 50-m2 piston. What force needs to be exerted on a 1.00 m2 piston to lift the crate? So.. 2,000N* 1m2/50m2=40
Right?
yep
What is the unit of 40?
what is: N m^2/m^2 ??
I wish I knew....
Unit's confuse me
I think it's Nm^2
think of them as variables instead
no, if the Force on the left is in Newtons, then the force on the right will be in Newtons ....
So That means it is N?
but regardless of the fact .. N m^2/m^2 , anything divided by itself is equal to 1 N*1 = N
Because the m^2 cancel each other out
So my final answer should be 40N?
thats what all the parts togheter form ... yes. assuming i recall this material correctly :)
Thanks @amistre64 :D
youre welcome
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