Question

1/x^2*x^17

Answer 1

\[\frac{ 1 }{ x ^{2} } * x ^{17}\]

Answer 2

@terenzreignz I"M BACCKKKK

Answer 3

Lol see if i got this right

Answer 4

Please :)

Answer 5

OK the fraction becomes
\[\frac{ 1^{1} }{ x ^{^{17}}}\]

Answer 6

stop :)

Answer 7

If I times x by x I get
(1^1)(x^19)

Answer 8

Okay, let's review another law that comes into play:
\[\Large a^{-m}= \frac1{a^m}\]
That is to say, if an exponent is in the denominator, then it's the same as if it were in the numerator but the exponent 'negated' (changed sign)

So, that said, what's another way to write
\[\Large \frac1{x^2}=\color{red}?\]

Answer 9

x^-2/1

Answer 10

Forget the 1

Answer 11

\[\Large \frac1{x^2}= x^{-2}\] should suffice

Answer 12

yeah

Answer 13

It's just x^-2

Answer 14

That's right.
So...
\[\Large x^{-2}\cdot x ^{17}\]
Basic law of exponent comes to play... just add the exponents :)

Answer 15

So that gives me
x^-2 *x17
x^15

Answer 16

That is correct :)

Answer 17

You want a few drills like last time?

Answer 18

How about this one
\[(\frac{ -x ^{5} }{ 2 }) \]

Answer 19

wouldn't that be
-x^5/2^1

Answer 20

Wait what?
\[\Large \frac{-x^5}2{}\]?

Answer 21

Or \[\Large \frac{x^{-5}}2\]?

Answer 22

Here let me draw it