suppose event A is included in (that is, is a subset of) event B. Then P(A and B) = P(B) True or False?
If A is a subset of B, then we can visually represent it like this |dw:1377027922946:dw|
now if you're in both sets A and B, then you are here |dw:1377027968627:dw|
is that the same as being in set B (all of set B)?
Yes
depends on of A is defined as a "proper" subset, or just as a subset
it says its just a subset
but if you're in set B, you could be out here |dw:1377028085492:dw|
so there is no guarantee that P(A and B) = P(B)
oh I see
the only way for P(A and B) = P(B) to be true is if A = B
at best: P(AnB) = P(A) if P(A) = P(B), which can occur of A is a subset of B (B is a subset of itself after all) but this is a special case
okay I get it now thanks guys!
yw
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