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Find the exact value by using a half-angle identity. sin 7 pi/8
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\(\bf \cfrac{7}{8} \times 2 \implies \cfrac{7}{4}\\ sin\left(\frac{7 \pi}{8}\right) \implies sin\left(\cfrac{\frac{7 \pi}{4}}{2}\right)\)
and surely \(\bf \cfrac{7 \pi}{4}\) will be in your Unit Circle
would it be \[1/2\sqrt{2-\sqrt{2}}\]
as the final result
\(\bf sin\left(\cfrac{\frac{7 \pi}{4}}{2}\right) \implies \sqrt{\cfrac{1-\left(-\frac{\sqrt{2}}{2}\right)}{2}}\\ \sqrt{\cfrac{1+\frac{\sqrt{2}}{2}}{2}} \implies \sqrt{\cfrac{\frac{2+\sqrt{2}}{2}}{2}} \implies \cfrac{\sqrt{2+\sqrt{2}}}{2}\)
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