Find the equation of the line tangent to y=cosx at x=pi/6
if a line has slope m then what would be the slope of the line perpendicular to it.??
The opposite reciprocal of m
1. Find the first derivative of your function. 2. That is the slope function. Plug pi/6 into the slope function to find the slope of the tangent at pi/6 3. Plug pi/6 into the original function and find y 4. (pi/6,y) is a point on the tangent. 5. Use the slope from step 2 and the point from step 4 and write the equation of the line using point-slope form.
We didn't learn what a derivative is. All I know is I'm supposed to plug pi/6 back into the formula f(x)=cosx and then use the formula (y2-y1)/(x2-x1) with the coordinates (pi/6 , cospi/6) and (x , cosx)
Then I would choose an x value close to pi/6 so that the slope would be more accurate.
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