Question

(15/x^2+3x)+(3/x)+(5/x+3)

Simplify if possible

Answer 1

first, find the common denominator and multiply each term by the common denominator to rid off the fraction, then you can easily simplify it

Answer 2

I got \[(8x^3+48x^2+74x)/((x+3)(x^3+3x^2))\]

Answer 3

(x^2+14x+18)/(x^2+3x)

Answer 4

how did you arrive to that answer

Answer 5

right or wrong

Answer 6

\[\frac{15}{x(x+3)}+\frac{3}{x}+\frac{5}{x+3}\]

Answer 7

\[\frac{15}{x(x+3)}+\frac{3(x+3)}{x(x+3)}+\frac{5x}{x(x+3)}\]

Answer 8

Now, all the denominators are the same so we will simply add the numerators:

Answer 9

\[\frac{15+3(x+3)+5x}{x(x+3)}=\frac{15+3x+9+5x}{x(x+3)}=\frac{8x+24}{x(x+3)}\]

Answer 10

Thank you so much I greatly appreciate your help, you're the best.

Answer 11

yw

Answer 12

good Mertsj

Answer 13

Whoops. Not quite done:
\[\frac{8x+24}{x(x+3)}=\frac{8(x+3)}{x(x+3)}=\frac{8}{x}\]

Answer 14

Good looking out =^^=