x + 1 - 2 square root x + 4 = 0
\[x+1-2\sqrt{x+4}=0\] is this what the equation is supposed to look like?
yes, thank you
no problem, so you have to isolate the x, correct?
yes
so -2 sr x + 4 = -x -1
ok, so the x+1 is attached? because there are no parenthesis around them so i dont believe they are attached to each other, which means you can subtract just thee one so you will get: x-2srx+4=-1
Then is it x squared + 16 x - 32 = -1?
add \(2\sqrt{x+4}\) to both sides and start with \[x+1=2\sqrt{x+4}\] then square both sides
Ahhh, ok I think I see it now and in the end x = 5?
5 works for sure you might get two answers though, maybe not
Yes, of course. You rock! Thanks!
oh no only one solution, just 5
yw
Ok, phew. I was just checking to be sure lol
good work!
:)
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