How do i find the domain and range for h(t) = cot t
are there any restrictions on t?
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i think i answered the wrong question. so sorry about that. you can take away the medal you gave to me. so sorry about that.
there arent any restrictions
Mhm, why do you say that
you asked if there were restrictions on t and thats my answer
what I mean is, is there a value of t that will give you a discontinuity (is there a hole or a verticle asymptote in the graph)?
I've been in calc for 4 days i dont know what you mean forgive me
do you know what the domain is of \[(x+1)(x-1)/(x-1)\]?
no
the refers to the valid range of inputs (in the above case x, in your question it is t). in the above case all real numbers would satify the equation EXCEPT for x = 1, because at that point you have a 0 in your denominator. you can think of domain (sort of) as "what input will make my function break the rules of artimatic. my domain is everything except those numbers."
are there any values of t that will make the cosine function break the rules of arithmatic (negative square roots, zeroes in denominators,etc etc)?
is t going to be a degree or radian value?
we use radian's about 99% of the time when we use trig functions.
that doesnt answer my question..
The domain are the x-values such that the function will have a finite real value. You can plug in basically anything as x, except the values that cause h(x) to become infinite. In this case, since tan 0 = 0, then cot 0 = inf. Which means 0 is not included in the domain. And its equivalents, such as pi, 2pi, 3pi, 4pi etc. are also not included in the domain. So, the domain is all real numbers excluding multiples of pi. h(x), on the other hand, can range anywhere from negative infinity to positive infinity. It has no limits to its values. Hence, the range is all real numbers.
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