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for \(f(x)=log_3(x-2)\) find \(f^{-1}(x)\)
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\[\log_3(y-2)=x\] solve for \(y\) in two steps
woah woah woah....what?
1) rewrite in equivalent exponential form 2) add 2 to both sides
where did you get \(\log_3(y-2)=x\)?
this is the way you are usually taught to find an inverse function right? if say \(f(x)=2x+3\) then to find \(f^{-1}(x)\) you write \[x=2y+3\] and solve for \(y\)
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ohhh...k i get it...gimme a sec
i just did the same thing
so it would be \(3^x=y-2\)\[3^x+2=y\]\[f^{-1}=3^x+2\]
thanks! @satellite73 :)
yw
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