if \(f(x)={e^{ln~x}\over x}\), then what is \(f(1)\)?
Are you serious?
i'm confused because the answer should b x but thats not one of the choices..
Why is the answer \(x\)? Don't you see that \(e^{ln(x)}\) = \(x\)
Therefore, if you have \(\frac{x}{x}\)....
oh wait, that would make it 1...
omg..
noob.
i know.. .-.
hey quick question..if a function is symmetric with respect to the origin that makes it symmetric to the x and y axes as well, right?
@abb0t
okay well the question says: if the curve of \(f(x)\) is symmetric with respect to the origin, then it follows that f(0)-0 f(-x)=-f(x) f(x)=f(-x) f(x) is also symmetric with respect tot he x and y-axes f(-x)=-f(-x)
@dumbcow
@dan815
i reposted it at http://openstudy.com/study#/updates/52144845e4b0450ed75e04fb
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