Solve (x^2(x-2))^3/sqrt(x+4)
Do you want to find domain or something?
The equation you give and your drawing is different. I presume the drawing is correct? You also don't indicate what you need to solve? Simplify? Find the derivative?
It just says solve. Also, I forgot to draw the less than zero. My bad.
|dw:1377066511809:dw|
Yes. My paper says "solve the inequality."
Do you have the Answer to this question in some answer key or something?
Nope. That's why I'm stuck on this question. I have no way of finding out what it wants from me as an answer.
See I don't want to confuse you or tell you something wrong! But I got the answer as (0,2) @ankit042 ?
I'll try that for now. Thanks for helping. :)
okay so here's what I did! You can get 2 inequalities actually In the denominator = x+4 > = 0 And the numerator remains as it is!
i think the answer is \[-4<x<2\]
correction. \[(-4,0) \text{ or } (0,2)\]
I'll probably find the answer tomorrow. Hopefully it's one of these.
:)
y < 0 so x cannot be 0. sirm3d's first answer should then be the correct one: -4 < x < 2 x > -4 to prevent the square root of a negative number and x < 2 as y = 0 if x = 2 and y < 0.
Join our real-time social learning platform and learn together with your friends!