I am sure that this one is different! The standard enthalpy change of formation values of two oxides of phosphorus are :
P4 + 3O2 --P4O6 delta H of formation= -1600kj mol-1
P4 + 5O2 -- P4O10 deltaH of formation= -3000kj mol-1

What is the enthalpy change, in kJ mol-1, for the reaction below?
P4O6 + 2O2 -- P4O10

Question

I am sure that this one is different! The standard enthalpy change of formation values of two oxides of phosphorus are : 
P4 + 3O2 -->P4O6 delta H of formation= -1600kj mol-1
P4 + 5O2 --> P4O10 deltaH of formation= -3000kj mol-1

What is the enthalpy change, in kJ mol-1, for the reaction below?
P4O6 + 2O2 --> P4O10

chmvijay · Answer

lol this i already solved it MAN

frostbite · Answer

@amsterdam11 would you take my word for it if I say this is no different then the others? :)

anonymous · Answer

I got +1200 but its wrong

frostbite · Answer

Lets see what you have tried.

anonymous · Answer

Apologies, I just miscalculated something, the answer I have now is -1400!

frostbite · Answer

Much better! :)

anonymous · Answer

Ok sorry and thanks !

frostbite · Answer

No need to be sorry. You solved it your self. A thumbs up for that.

frostbite · Answer

And here you have it:
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