what is the vertex of the parabola y=x^2-6x+7?

Question

anonymous · Answer

using completing the square, transform the given equation into vertex form:$$y=a(x-h)^{2}+k$$
where (h,k) is the coordinates of the vertex.

luigi0210 · Answer

Using derivatives you get:
y'=2x-6
So it's at x=3
:3

luigi0210 · Answer

Data's way works better xD

anonymous · Answer

Luigi's way is much easier:)

anonymous · Answer

wait iv seen the h,k thing before but i dont get what you mean?

anonymous · Answer

check this for further understanding: http://www.mathsisfun.com/algebra/completing-square.html

campbell_st · Answer

an easy was is the find the line of symmetry for the parabola... as the vertex is on the line of symmetry

$$y = ax^2 + bx + c$$

the line of symmetry is 

$$x =\frac{-b}{2a}$$

in your question b = -6 and a = 1

substitute them to find the equation and them substitute the value of x you found into the original equation to get the ordered pair for the vertex. 

is a little easier than factoring to a perfect square

anonymous · Answer

oh my gosh that was perfect thankyou will do! thanks everyone!